Physics, asked by youmeiq01, 3 months ago

Block is displaced by 3 m when a force of 200 n is applied on it on an inclined surface which is at an angle of 50o with the horizontal. What is the work done? Select one:

Answers

Answered by Naveen670
0

Answer:

GiveN :

Displacement (s) = 3 m

Force applied (F) = 200 N

Angle of inclination (Θ) = 50°

To FinD :

Work Done to displace book

SolutioN :

Use formula for work done :

⇒Work Done = Force.displacement

⇒W = F.s

⇒W = Fs cosΘ

⇒W = 200 * 3 * cos50°

⇒W = 600 * cos50°

⇒W = 600 * 0.64

⇒W = 384 (approx.)

\therefore∴ Work Done to displace book is 384 J (approx.)

_______________________

Additional Information :

• When force is applied on an object, and object displace in the direction of force applied, then work is said to be done.

• SI unit of Work Done is Joule (J).

• Force and displacement are vector quantities, and Work done is scalar quantity. Because when two vector quantities are multiplied then their resultant is always scalar quantity.

Answered by mudit3442
0

Answer:

ब्लॉक 3 मीटर से विस्थापित किया जाता है जब 200 का एक बल n एक झुका सतह है जो क्षैतिज के साथ 50o के कोण पर है पर उस पर लागू किया जाता है काम एक का चयन किया है क्या

GiveN : Displacement (s) = 3 m. Force applied (F) = 200 N. Angle of inclination (Θ) = 50°

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