Block of mass 0.5 kq is moving with a speed of 2 m/
n a smooth surface. it strikes another mass of 1kg
and then they move together as a single body.
the energy loss during collision is ..ANSWER IS 0.675.
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Answer:
Explanation:\
doing conservation of momentum
new v = 0.5*2/1+0.5
= 1/1.5 =2/3
energy loss = k.e final-k.e initila
= 0.5(1.5*(0.66*0.66) - 0.5*2*2)
= -0.6666
therefore energyloss = 0.6666n-m
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