Question

block of mass m = 1 kg moving on a hortzontal surface with speed v, = 4 ms* enters a rough patch ranging from x = 0.10 m to r= 2.01 m. The retarding force E on the block in this range is inversely proportional to x over this range. F, for 0.1 < *< 2.01 m = 0 for x< 0.1 m and x> 2.01 m where, k = 04 ]. What is the final kinetic energy and speed v, of the block as it crosses this patch ​

Answer 1

Therefore, the velocity of the mass as it crosses the rough patch is 1 m/s