block of mass m having charge q is placed on smooth horizontal table and is connected to a wall through an unstressed spring of spring constant k . A horizontal electric field is switched on. Find the amplitude of the resulting SHM on the block.
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Consider the situation shown in the below figure.

Then,
F = qE, F = –Kx Where x = amplitude qE = – Kx or x = −qEK
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Then,
F = qE, F = –Kx Where x = amplitude qE = – Kx or x = −qEK
Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
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