block of mass M1 = 8 kg the bar of mass entry question 2kg placed on a rough surface lie on the smooth flow of elevator extending with an acceleration G by for the coefficient of friction of is 1 by 5 between M1 and M2 and the plant
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let the frictional force between plank and bar is f
f=µN
N=pseudo force+weight of the bar
=20+2g/4=25N
f=25x1/5 = 5N
acceleration of the bar = force on bar/mass of bar = frictional force/mass
=5/2
=2.5m/s2
acceleration of the plank=30-5/8
=25/8 m/s2
Thanks
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