block of maths 10 kg lying on smooth horizontal surface is being pulled by means of a rope of mass 2 kg. if a force of 36N is applied at the end of the rope, the tension at the midpoint of the rope is
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this is you're answer mate.
Given,
Block of mass is 10kg
Rope of mass is 2kg
F=36N
So,
At midpoint A of the rope
F=ma
36=(2+10)a
a=
12
36
=3m/s
2
Now,
36−T
A
=
2
m
×a
36−T
A
=
2
2
×3
T
A
=36−3=33N
Where T
A
is the Tension at point A
solution
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