Question

block of weight wis kept on smooth inclined face of a cart. The block is tied to a vertical wall with the help of a string as shown in the figure. The whole system is in equilibrium. Find the friction force applied by the ground on the cart.​

Answer 1

Thus the force acting on the block is F = √3 W / 4.

Explanation:

Given data:

We are given that The block is tied to a vertical wall with the help of a string.

Solution:

N = W cos θ and N sin θ = F  

W cos θ sinθ = F

or F = W √3 / 2 x 1 / 2

⇒ F = √3 W / 4

Thus the force acting on the block is F = √3 W / 4