block of wood weighing 4N is placed on a horizontal table it is then pulled by means of spring balance attached to one of it ends,the block just begins to move when the spring balance record in horizontal force of 2.5N then what is the co-efficient of static friction
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Given: weight of block = 4 N.
The block just begins to move when a force of 2.5 N is applied to the block.
To find: The frictional force when the block is applied by a force of 2 N.
Concept: Friction can be of 2 types:
1. Static friction/Limiting friction: It is observed when body is stationary. This friction goes on increasing with increase in force until the critical force is reached.
2. Dynamic force: It is observed when the body starts moving. It is lesser in magnitude than static friction.
Calculation: In this case, the critical force is 2.5 N.
But if a force of 2 N is applied, the friction force will also be 2N (static friction) so as to prevent the object from moving.
Conclusion: Frictional force will be 2N.
The block just begins to move when a force of 2.5 N is applied to the block.
To find: The frictional force when the block is applied by a force of 2 N.
Concept: Friction can be of 2 types:
1. Static friction/Limiting friction: It is observed when body is stationary. This friction goes on increasing with increase in force until the critical force is reached.
2. Dynamic force: It is observed when the body starts moving. It is lesser in magnitude than static friction.
Calculation: In this case, the critical force is 2.5 N.
But if a force of 2 N is applied, the friction force will also be 2N (static friction) so as to prevent the object from moving.
Conclusion: Frictional force will be 2N.
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