Question

Block shown in figure moves with constabt velocity 10 towards right all surface in contact are rough the friction force applied by b on a is

Answer 1

Answer:

Given that both block move with constant velocity.

So, a=0

f=m  

A

​  

a=m  

A

​  

×0=0

f=0

The blocks move with constant velocity. Thus the net force acting on the system is 0.

External force acting on A 20N. Since the net force acting on B is 0, friction must be 20N in opposite direction of external force.

External force acting on A is 0 and net force on A is 0. Hence friction on A due to B is 0.

Hence, answer is 0.

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