Question

block with a mass of 20 gram moves at a constant velocity on a rough horizontal floor with 2 N applied force. Find the frictional force​

Answer 1

Explanation:

mg−T=ma

⇒30−27=3a

⇒a=1 m/s

2

T−μMg=Ma

⇒27−μ×200=20

⇒μ=

200

7

=0.035