Blocks shown in figure moves with constant velocity 10 m/s towards right. All surfaces is contact are rough. The friction force applied by B on A is.
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The blocks move with constant velocity. Thus the net force acting on the system is 0.
External force acting on A 20N. Since the net force acting on B is 0, friction must be 20N in opposite direction of external force.
External force acting on A is 0 and net force on A is 0. Hence friction on A due to B is 0.
Hence, answer is 0.
External force acting on A 20N. Since the net force acting on B is 0, friction must be 20N in opposite direction of external force.
External force acting on A is 0 and net force on A is 0. Hence friction on A due to B is 0.
Hence, answer is 0.
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Answer:
Zero Newton
Explanation:
Given that blocks are moving with constant velocity, it means that all forces on block are balanced and net force is zero.
external force on block A is 0 Since net force on block A is zero therefore friction force on A due to B must be Zero
Similarly, external force on block B is 20 N . since net force on block B is zero therefore friction force on block B must be 20 N.
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