BO and CO are angle bisctors. If <A = 50 degree, then <BOC = ?
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As BO and CO are the angle bisectors of external angles of△ABC, Then
∠1=∠2
∠4=∠3
We know, ∠A+∠ABC+∠ACB=180
∘
…eqn(1)
And ∠ABC=180−2∠1
∠ACB=180−2∠4
Putting it in the eqn (1), we get
∠A+180−2∠1+180−2∠4=180
⇒∠1+∠4=90+
2
1
∠A…eqn(2)
Also we know from the figure, ∠BOC+∠1+∠4=180
∘
∠BOC=180−∠1−∠4
From eqn (2)
∠BOC=180−90−
2
1
∠A
⇒∠BOC=90
∘
−
2
1
∠A
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