Question

BO and CO are Bisector of angleB and angle C respectively. if angle BOC = 120° find angle BAC​

Answer 1

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Given :-

• A ️ABC in which BO & CO busects /_B & /_C and /_BOC = 120°.

TO FIND :-

• /_BAC

Solution :-

Since BO bisects /_ABC

Therefore, /_ABO = /OBC = y (say)

Also, CO bisects /_ACB

Therefore, /_ACO = /OCB = z (say)

Now, in ️ BOC

/_AOB + /_BCO + /_CBO = 180° (Using angle sum property)

=> 120° + z + y = 180°

=> z + y = 60°......(1)

Now, in ️ ABC

/_BAC + /_ACB + /_ABC = 180°

/_BAC + 2y + 2z = 180°

/_BAC + 2(y + z) = 180°

/_BAC + 2 × 60° = 180° (Using (1))

/_BAC = 180° - 120°

=> /_BAC = 60°

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Answer 2

Answer:

this is correct..................