Question

BO and CO are external bisertors of angle B and angle C of a triangle ABC . intersecting at 0. If angle A =60 angle ABC =70 FIND ANGLE BOC​

Answer 1

Answer:

triangle ABC

triangle ABCAngle A=60 degree

triangle ABCAngle A=60 degreeAngle ABC=70 degree

triangle ABCAngle A=60 degreeAngle ABC=70 degreeAngle BAC+angle ABC+angle ACB=180 degree

triangle ABCAngle A=60 degreeAngle ABC=70 degreeAngle BAC+angle ABC+angle ACB=180 degreeSubstitute the values

triangle ABCAngle A=60 degreeAngle ABC=70 degreeAngle BAC+angle ABC+angle ACB=180 degreeSubstitute the valuesIn triangle BOC

triangle ABCAngle A=60 degreeAngle ABC=70 degreeAngle BAC+angle ABC+angle ACB=180 degreeSubstitute the valuesIn triangle BOCAngle OBC=70 degree

triangle ABCAngle A=60 degreeAngle ABC=70 degreeAngle BAC+angle ABC+angle ACB=180 degreeSubstitute the valuesIn triangle BOCAngle OBC=70 degreeAngle BCO=50 degree

triangle ABCAngle A=60 degreeAngle ABC=70 degreeAngle BAC+angle ABC+angle ACB=180 degreeSubstitute the valuesIn triangle BOCAngle OBC=70 degreeAngle BCO=50 degreeBecause OB and OC are external bisector of Angle B and angle C.

triangle ABCAngle A=60 degreeAngle ABC=70 degreeAngle BAC+angle ABC+angle ACB=180 degreeSubstitute the valuesIn triangle BOCAngle OBC=70 degreeAngle BCO=50 degreeBecause OB and OC are external bisector of Angle B and angle C.Angle OBC+angle BCO+angle BOC=180 degree

triangle ABCAngle A=60 degreeAngle ABC=70 degreeAngle BAC+angle ABC+angle ACB=180 degreeSubstitute the valuesIn triangle BOCAngle OBC=70 degreeAngle BCO=50 degreeBecause OB and OC are external bisector of Angle B and angle C.Angle OBC+angle BCO+angle BOC=180 degreeHence, angle BOC=120 degree

Answer 2

Answer:

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