Question

BO and CO are the bisector of the angle B and C respectively of a triangle ABC if OX perpendicular BC and OY perpendicular AB prove that triangle BOY congurent triangle BOX ,OX=OY

Answer 1

Step-by-step explanation:

In ∆BOY and ∆BOX

BO is common

Angle YBO=Angle OBX(As BO bisects B)

Angle OYB=Angle OBX(each 90･ﾟ)

Hence....

∆BOY is congruent to ∆BOX(AAS)

Therefore...

..OY=OX (cpct)

Hence proved...

Hoping to be helpful....