Question

BO50°
In the figure, ZABD= 3 ZDAB and ZBDC = 96º. Find ZABD.
B
이 이
96
81
ID
of ADO​

Answer 1

In △ABC,

∠ABD=3∠DAB (given)

and ∠BDC=96°

∠BDC+∠BDA=180° (linear pair)

⇒96° +∠BDA=180°

⇒∠BDA=180° −96° =84°

In △ABD,∠ABD+∠DAB+∠BDA=180° (angle sum property)

⇒3∠DAB+∠DAB+84⁰=180°

⇒4∠DAB=180°−84° =96°

⇒∠DAB= 96°/4 =24°and

∠ABD=3∠DAB=3×24°=72⁰