Question

Board exam tmrw, plz solve!
If 3sinA = 4cosA ; find i)sinA ii)cosA iii)tan²A - sec²A

Answer 1

Hey Mate.....

Here's ur answer...

3sinA =4cosA

SinA /cosA =4/3

tanA =4/3

using Pythagoras theorem,

hypotenuse =5

perpendicular=4

base=3

1)sinA =P/H

=4/5

2)cosA=B/H

=3/5

3)tan^2A=(4/3)^2

=16/9

sec^2A=(5/3)^2

=25/9

.˙.tan^2A-sec^2A=(16/9)-(25/9)

=(-9/9)

=-1

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