BOAX is a quadrant of a circle of radius 6 centimetre . AB is diameter of semi-circle ABY .find the area of shaded portion.
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Area of quadrant = 1/4 × π × 6²
= 22 × 9 / 7
= 198/7 cm²
Area of triangle = ½ × b × h = ½ × 6² = 18 cm²/
Area of segment, x = 198/7 - 18 = 72/7
Area of semicircle ....
Diameter of semicircle = hypotenuse of ∆ BOA
So... Diameter = √(6² + 6²)
= √72
= 6√2 cm
Radius of semicircle = 3√2 cm
Area of semicircle =
Area of shaded region = 198/7 - 72/7
= 126/7= 18 cm²
Hope it helps
Area of quadrant = 1/4 × π × 6²
= 22 × 9 / 7
= 198/7 cm²
Area of triangle = ½ × b × h = ½ × 6² = 18 cm²/
Area of segment, x = 198/7 - 18 = 72/7
Area of semicircle ....
Diameter of semicircle = hypotenuse of ∆ BOA
So... Diameter = √(6² + 6²)
= √72
= 6√2 cm
Radius of semicircle = 3√2 cm
Area of semicircle =
Area of shaded region = 198/7 - 72/7
= 126/7= 18 cm²
Hope it helps
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