Bob of a simple pendulum has mass 1 kg andcharge 9o. Tension in the string doubles whenanother charge qo is fixed at position Pas shown.Time period of simple pendulum for the smalloscillation, is n s (another charge qo remains fixedat P). Find value of n. (g = 114]P1 = 6 m1 = 6 m
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Answer is 2√3 second
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