Bob purchased some number of pencils and divided it amongst his 3 friends. He gave it to them, one at a time. To each of
them, he gave half of the pencils he had then, and two more besides. He kept one pencil with him. How many pencils did
he purchase initially?
1.20
2.26
3.31
4.36
Answers
Answered by
3
Answer :-
In last bob kept 1 pencil with him .
So, Pencil bob has before, giving to third friend is :-
→ x - (x/2 + 2) = 1
→ x/2 - 2 = 1
→ x/2 = 3
→ x = 6 .
similarly, Pencil bob has before, giving to second friend is :-
→ x - (x/2 + 2) = 6
→ x/2 - 2 = 6
→ x/2 = 8
→ x = 16 .
therefore, Pencil bob has before, giving to first friend is :-
→ x - (x/2 + 2) = 16
→ x/2 - 2 = 16
→ x/2 = 18
→ x = 36 (Ans.4)
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