bob uses two sizes of square tiles, tile A and tile B, to tile his bathroom. the area of tile A is 20 square inches, and the area of tile B is 24 square inches. the length of tile B is greater than the length of tile A by approximately how many inches?
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Answer: approximately 0.43 inches.
Step-by-step explanation:
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Given : square tiles
Tile A of area 20 sq inches and
Tile B of area 24 sq inches
To Find : the length of tile B is greater than the length of tile A by approximately how many inches
Solution:
Area of Square = side²
=> Side length = √( area of square)
length of tile B = √24 = 4.899 inch
length of tile A = √20 = 4.472 inch
the length of tile B is greater than the length of tile A = 4.899 - 4.472
= 0.418 inches
≈ 0.42 inches
the length of tile B is greater than the length of tile A by approximately 0.42 inches
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