Question

bob wants to cover a room of 4m long and 3m wide by square tiles. if each square tile is of side 0.5m , then find the cost of tiles required to cover the floor of the room at the rate of rupees 9 per tile.​

Answer 1

Answer:

48 tiles

Length of floor = 3m

Width of floor = 4m

Since floor is in rectangular shape

Area of floor = Length * Width

= 3 * 4

= 12 square meters.

Side of square tile with which Bob wants to cover the floor is 0.5m

Area covered by each square tile = side^2side

= 0.5^20.5

= 0.25 m^20.25m

No.of tiles required to cover the floor:

=$\frac{\text{area of floor}}{\text{area of each tile}}$

area of each tile

area of floor

=$\frac{12}{0.25}$

0.25

12

=4848

Thus 48 tiles are required to cover the floor.