Question

Bob wants to cover the floor of a room 3m wide and 4m long by squared tiles. If each square tile is of side 0.5 m,then find the no. Of tiles required to cover the floor of the room

Answer 1

Answer:

48 Tiles

Step-by-step explanation:

Area of floor to be tiled = length * width of floor

Area of floor to be tiled  = 4 m * 3m = 12 m²

Area of a tile = 0.5 m * 0.5 m = (5/10)*(5/10)  m²

= (25/100) m²

=  1/4 m²

Number of tiles required =  Area of floor/ Area of tile

Number of tiles required = 12/ (1/4)

= 12 * 4

= 48 tiles

Answer 2

➥Question

• Bob wants to cover the floor of a room 3 m wide and 4 m long by squared tiles. If each square tile is of side 0.5 m, then find the number of tiles required to cover the floor of the room.

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$\large{\underbrace{\underline{\mathrm{Understanding\:the\:concept:}}}}$

( In the given question ),Bob wants to cover its floor of a room is 3m wide and 4m long by squared tiles. Each square tiles is of side 0.5m, And we have to find the number of tiles to cover the floor.

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$\huge\bold{Let's\:solve}$

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Total area of tiles must be equal to the area of the floor of the room.

$\large \sf { Length \:of\:the\:room\:=\:4m}$

$\large \sf { Breadth \:of\:the\:room\:=\:3m }$

$\large \sf { Area\:of\:the\:floor\:=(L×B) }$

$\large \sf { =4m\:×\:3m=\:12sq\:m }$

$\large \sf { Area\:of\:1\:square \:tile=\:Side×Side}$

$\large \sf { =0.5m\:×\:0.5m }$

$\large \sf { =\:0.25sq\:m }$

$\large \sf number \: of \: tiles \: = \frac{area \: of \: the \: floor}{area \: of \: one \: tile}$

$\large \sf = \frac{12}{0.25} = \frac{1200}{25} = 48 \: tiles$

　　　　　 $\large{\underline{\boxed{\mathfrak{48\:tiles}}}}$

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Link of the same question:

https://brainly.in/question/34741986