Question

∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC, 
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90

∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC, 
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90

∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC, 
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90

∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC, 
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90

∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC, 
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90

∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.
Therefore, ∠BOC=2n
∠OCB=m
Since, OB = OC = radius of the circle = m
Thus, in Δ OBC, 
∠OCB+∠OBC+∠BOC=180∘
2m+2n=180
⇒m+n=90

​

Answer 1

Answer:

Metamorphic rocks started out as some other type of rock, but have been substantially changed from their original igneous, sedimentary, or earlier metamorphic form. Metamorphic rocks form when rocks are subjected to high heat, high pressure, hot mineral-rich fluids or, more commonly, some combination of these factors

Explanation:

∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.

Therefore, ∠BOC=2n

∠OCB=m

Since, OB = OC = radius of the circle = m

Thus, in Δ OBC, 

∠OCB+∠OBC+∠BOC=180∘

2m+2n=180

⇒m+n=90

Answer 2

here is your answer dear

don't report my answer

Can you please give me 20 point questions