bodies of mass 1kg and 2kg are connected by a very light string passed over a clamped light smooth Pulley if the system is released from rest find the acceleration of the two masses in the tension in the string
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Answer:
Here is the Answer = g÷3
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Answer:
this is you're answer mate.
Explanation:
m1 = 1 kg
m2 = 2kg
a= m1g / m1 + m2
a= 9.8 / 3
a1= 3.2 m/s²
a= 19.6 / 3
a2= 6.53 m/s²
T1=1 x 3.2= 3.2 N
T2= 2x 6.53 = 13.06
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