bodies of masses 4 kg and 2 kg are attached at the ends of massless rod. the position of 4 kgs and 2 kgs are (2i+5j) m and (4i+2j) m. then the position of centre of mass of the system is
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Answer:
Length of rod=
(2−4)
2
+(5−2)
2
=
4+9
=
13
Center of mass co-ordinate in M(x,y)
x=
3+2
3×2+4×2
=
5
14
y=
5
3×5+2×2
=
5
19
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