Question

BODMAS 4 + 5 [{-10 x (25 - 13 - 3)} ÷ (-5)]

Answer 1

So we have to solve the following question using BODMAS.

BODMAS is ⇒

• Brackets
• Of
• Division
• Multiplication
• Addition
• Subtraction

Whenever we solve any question or problem in maths we should make sure to apply BODMAS.

So first we do the simple brackets.

Here there is only one operation, subtraction, in brackets so we directly solve it.

4 + 5 [{-10 x 9} ÷ (-5)]

Now we solve the curly brackets.

Here there is only one operation, multiplication, in brackets so we directly solve it.

4 + 5 [{-90} ÷ (-5)]

Now we solve the box bracket.

Here there is only one operation, divison, in brackets so we directly solve it.

We also have to apply the integer law here which is  ⇒ - ÷ - = +

4 + 5 [{-90} ÷ (-5)]

4 + 5 × 18

Now we do the multiplication first.

4 + 90

Now since there is only one operation left, addition, we directly solve it.

4 + 90 = 94

∴ 4 + 5 [{-10 x (25 - 13 - 3)} ÷ (-5)] = 94

Answer 2

Answer:

=> 94

Step-by-step explanation:

Given that:-

$4 + 5 [\{-10 \times (25 - 13 - 3)\} \div (-5)]$

To Find:- The value of the expression,

By using the method of BODMAS,

BODMAS:-

  B= bracket

  O= order

  D= division

  M= multiplication

  A= addition

  S= subtraction

As we have,

=> $4 + 5 [\{-10 \times (25 - 13 - 3)\} \div (-5)]$

Simplifying it further, we get

=> $4 + 5 [\{-10 \times 9\} \div (-5)]$

By performing multiplication,

=> $4 + 5 [\{-90\} \div (-5)]$

=> $4 + 5 \times 18$

=> $4 + 90$

Add the numbers, we get

=> $94$

Hence, the required solution is 94.