Question

body
9. A body starting with an initial velocity of
4 m/s, moves with a uniform acceleration of
0.5 m/s2. After some time its velocity becomes
6 m/s. Calculate the time taken by the body to
attain this velocity and the distance covered
by it during this time interval.​

Answer 1

Answer:

v=u+at

6=4+0.5*t

t=4 seconds

now,

2as = v*2 - u*2

2*0.5 * s = 36-16

s = 20m

Explanation:

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Answer 2

Answer:

20m is the answer...

Explanation: We know A = (V-u) / t

A= Acceleration

v=final velocity

u=Initial velocity

t=time As,

              A = (V-u) / t

Therefore,

           v=u+at

           6=4+0.5xt

            t=4 seconds

            now,

            2as = vx2 - ux2  

            2x0.5 x s = 36-16

            s = 20m

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