Body A with charge +2q is brought in contact with anothef identical uncharged body B and then removed. The charge on body B is
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A and B are two identical spherical charged bodies which repel each other with force =F
finite distance =
From the figure again, you can see C is placed at
2
r
. Now see the direction of force due to A on C.
F
AC
and force due to B on C F
BC
from simple coulomb's law you can answer as follows
F
AC
=
y
r
2
KQ.Q/2
=
r
2
2KQ
2
=2F
Now, F
BC
=
r
2
/4
K
Q
2
/4
=
r
2
KQ
2
=F
Then, resultant force according to diagram will be
F
resultant
=2F−F=F along F
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