Question

body acted upon by a force of 50 newton is displaced through a distance 10m in a direction making an angle of 60° with the force the work done by the force be
Hope you all will help me Pls.....

Answer 1

work done =FScos theta
=50×10×cos60
=50×10×1/2=250J

Answer 2

if the force acts with a angle of 60°..we have to take the component of force which is in the direction of displacement..
so F=fcos60°
work done = Fcos60°*10 m
work done =(50)/2*10
w=250 J

I HOPE THIS HELPS U.
Mark brainliest if it did so..