Question

body covers a total distance of 3s . The first s is covered with a velocity u the second s with v and the last s with w. Then, the average velocity during the whole

Answer 1

Let the total distance be x
case1
d=1/3x
s=u
t=d/t=1x/3u



case 2
d=1/3 x
s=v
t=1x/3 v

case3
d=`1/3 x
s=w
t=1 x/3w
total d=x
total time=1/3u+1/3v+1/3w=ux+vx+wx/3
avg speed= total distance/total time taken
=x/ux+vx+wx/3
=x/x(u+v+w)/3
solving it.......
avg speed=3/u+v+w