Question

body dropped from height 'h' find
velocity after 4 sec and 6sec​

Answer 1

main kya kar sakta hu???

you have mentioned time only. other details are not here

Answer 2

Explanation:

h = h

g = 10m/s^2

t1 = 4s

t2 = 6s

we know that

$v = u + at$

But for freely falling body,u(initial velocity = 0)

so,

$v = at$

$v= gt$

$v = (10)(4)$

$v = 40 {ms}^{ - 1}$

There fore ,velocity after 4s = 40 m/s

Velocity after 6s is given by

$v = g(6)$

$v = (10)(6)$

$v = {60ms}^{ - 1}$

There fore,velocity after 6s = 60 m/s

HOPE IT HELPS.....

PLEASE MARK AS BRAINLIEST