Question

body has a
4. A train travelling at 36 km h-'speeds up to 72 km h- in 10
seconds. What is the acceleration of the train?
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Answer 1

Answer:

a = 1m/s^2

Explanation:

Initial velocity u = 36 km/h = 36 x 1000/3600 m/s = 10 m/s

Final velocity v = 72 km/h = 72 x 1000/3600 m/s = 20 m/s

Time t = 10 s

Acceleration a = (v-u)/t = (20 - 10)/10 = 1 m/s2.