Question

body is dropped down from a height .What distance does it fall in first 4s of its motion, if g=10m/s 2​

Answer 1

Answer:

90 Metres

Explanation:

s = ut + 1 at^2

2

s = the distance travelled, which is what we are trying to find

u = is the initial velocity, which is 0.

t = the elapsed time, which is 4s

a = acceleration, which is g, or 10m/s

since u is 0, we simply have

s = 0 × 4 + 1 × 10 × 4^2

2

s = 5× 16

s = 90 metres

Distance = 90 Metres