Question

body is moving with an initial velocity of 30m/s and its velocity is increased to 45m/s in 5seconds find acceleration

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Answer 1

this is the right answer

Answer 2

Answer

Acceleration = 3 m/s²

Given

A  body is moving with an initial velocity of 30 m/s and its velocity is increased to 45 m/s in 5 seconds

To Find

Acceleration

Concept Used

Acceleration is defined as rate of change in velocity

$\to\ \rm{\orange{a=\dfrac{v-u}{t}}\ \; \bigstar }$

SI unit of acceleration is m/s²

SI unit of velocity is m/s

SI unit of time is second

Solution

Initial velocity , u = 30 m/s

Final velocity , v = 45 m/s

Time , t = 5 s

Acceleration , a = ? m/s²

Apply formula ,

$\to\ \rm a=\dfrac{v-u}{t}\\\\\to\ \rm a=\dfrac{45-30}{5}\\\\\to\ \rm a=\dfrac{15}{5}\\\\\to\ \rm{\red{a=3\ m/s^2\ \; \bigstar}}$

So , Acceleration , a = 3 m/s²

More Info

$\boxed{\begin{minipage}{4.5cm} \underbrace{\bf Equation's\ of\ motion}\ :\\\\\to\ \rm v=u+at\\\\\to\ s=ut+\dfrac{1}{2}at^2\\\\\to\ v^2-u^2=2as\\\\\to\ S_n=u+\dfrac{a}{2}(2n-1) \end{minipage}}$