Question

body is projected upwards with a speed of 40m/s. Then time taken to reach the highest point is​

Answer 1

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Answer 2

Answer:

Let the horizontal distance be H and

let the distance traveled in the last second be d

H=

2g

u

2

H=

19.6

1600

H=81.63m

Now time taken by the body to reach a height of 81.36 m=

g

2H

=4.08s

Now from equation of motion, we have

s=ut+

2

1

gt

2

H−d=(40)(t−1)−

2

1

g(t−1)

2

81.63−d=(40)(4.08−1)−

2

1

(9.8)(4.08−1)

2

d=4.85m