Question

Body is thrown horizontally from the top of the tower of height 5 metres it touches the ground at the distance of 10 metres from the foot of the tower initial velocity of the body is

Answer 1

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★ Gɪᴠᴇɴ ★

• Height of the tower = 5 m
• Range of projectile = 10 m

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☯ Tᴏ Fɪɴᴅ ☯

• Initial velocity of the projectile

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✪ Sᴏʟᴜᴛɪᴏɴ ✪

Time of flight → T = √2H/g

→ T = √2×5/10

→ T = 10s

Initial velocity of the projectile

→ u = R/T

→ u = 10/1

→ u = 10 m/s

★ Initial velocity of the body is 10 m/s

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Answer 2

Answer:

Initial velocity = 10 m/s

Explanation:

Given;-

              h = 5 m ( height of the tower )

              x = 10 m ( horizontal range )

Since,

              x = u Tf      [where Tf is time of flight]

So,

             10 = u √2h/g    [since, Tf = √2h/g]

             10 = u √2 × 5/ 10

             10 = u

Therefore, the initial velocity of the body is 10 m/s.