Question

Body moving with a velocity of 40m/s is brought to rest in 5 seconds.Calculate the retardation

Answer 1

Initial velocity =40m/s
Final velocity =0 m/s
Time taken =5 sec
We know
V=U+AT
0=40+A×5
A= - 8
Retardation =8 m/s²
Here negative sign indicates Retardation

Answer 2

Concept:

• One-dimensional motion
• Kinematics equations
• Acceleration and retardation
• Negative acceleration is what retardation signifies.
• A body's velocity could increase or decrease.
• A body experiences acceleration when its velocity changes.
• As a result, when a body's velocity increases, the acceleration is said to be positive, and when it decreases, the acceleration is said to be negative (Retardation).
• If a body's velocity is reducing, it is said to be retarded.

Given:

• The initial velocity of the body u = 40 m/s
• The final velocity of the body v = 0 m/s
• The time taken to bring the body to rest t = 5 s

Find:

• The retardation of the body

Solution:

We have to use the following kinematics equation

v = u +at

v = 0 m/s, u = 40 m/s, t = 5 s

0 = 40 + a(5)

-40 = 5a

a = -8 m/s^2

The retardation is 8 m/s^2.

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