Question

body moving with uniform acceleration
travels in the first 6 s and 180 m in the next 5s Find : (a) the initial velocity, and
the acceleration of the body​

Answer 1

Answer:

$distance \: covered \: in \: 6sec \\ = 180m \\ distance \: covered \: in \: 1sec \\ = \frac{180}{60} = 30m \\ distance \: covered \: in \: 5sec \\ = 30 \times 5 = 150m \\ initial \: velocity = \frac{180 + 150}{5 + 6} \\ = \frac{330}{11} = 30$

Step-by-step explanation:

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