Chemistry, asked by sunilsinghasna, 1 year ago

Body moving with velocity of 40m/s^2 is brought to rest in 5s calculate the disaccleration

Answers

Answered by Pranshukamra
2
hey friend,

in this question

u which means initial velocity=40m/s

v which is final velocity=0 as the object is being in rest.

t which we use for time=5sec

Formula of retardation =v-u/t
=0-40/5
=-8m/sec

hope it will help u
Answered by metalhobgoblin
0
since retardation =final velocity - initial velocity/time
your answer would be
0-40/5
=-40/5
=-8
therefore the retardation of the body is 8mt/sec^2
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