Body of mass 1 kg is kept at rest and constant for 6.0 newton start acting on it find the time taken by the body to move through a distance of 12 metre
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Answer:
By Newton's second law ------->
S = ut + 1/2 * gt^2
12 = 0 * t + 1/2 * 6 * t^2
12 = 3 * t^2
12/3 = t^2
4 = t^2
t = 2 second
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Given :-
- Mass → 1 kg
- Force → 6 N
- So, Acceleration → ?
_____
- Initial Velocity → 0 m/s
- Distance Travelled → 12 m
- Time Taken → ?
To Find :-
- The acceleration produced
- The time taken
Solution :-
As we know ,
F = ma
→ 6 N = 1 kg × acceleration
→ So, Acceleration = 6.0 m/s²
[ Formula Used :- ]
s = ut + ½ at² ★
Here,
s = 12 m
u = 0 m/s
t = ?
a = 6 m/s²
→ 12 m = 0 × t + ½ × 6 m/s² × t²
→ 12 m = 0 + 3 m/s² × t²
→ 12 m = 3 m/s² × t²
→ 4s² = t²
→ t = √4s²
→ t = 2s
So, The time taken was 2 s
Thank You !
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