Physics, asked by arshammalick13, 1 month ago

body of mass 10 kg from height 10 m is dropped . What will be its kinetic energy when it reaches the ground. Take g = 9.8 N/kg​

Answers

Answered by diyapardhi2006
0

Explanation:

[g=980 cm *s^(-2)] Potential energy at the initial position = mgh =10×9.8×10=980J . Let the final velocity of the body just before it touches the ground be v . Hence, kinetic energy gained =initial potential energy.

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