Question

body of mass 10 kg moving with velocity of 6 m/s.If a force of 20 N is applied on the body, find the velocity

after 4 second and distance travelled in that 4 sec


help me​

Answer 1

Answer:

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Answer 2

Answer:

A 10 kg body is moving with a velocity of 6 m/s. If a force of 20 N is applied to the body, the velocity  after 4 seconds is $14m/s$ and distance traveled in that 4 sec is $40m$

Explanation:

• We have two equations of motions to find the final velocity and distance traveled by an accelerated body

                        $v=u+at$     and     $s=ut+\frac{1}{2}at^{2}$

        where,

        u-initial velocity

        v-final velocity

        a-acceleration

        t-time

        s-distance

• from Newton's second law the force(F) on a body having acceleration (a) and mass (m) is   $F=ma$

From the question, we have

the initial velocity of the body $u=6m/s$

mass of the body $m=10kg$

the force applied on the body $F=20N$

so the acceleration of the body $a=F/m=20/10=2m/s^{2}$

the final velocity of the body after $t=4s$

⇒$v=6+2*4=14m/s$

distance traveled is $s=6*4+\frac{2*16}{2} =40m$