body of mass 10gram hits a target and penetrates 2 cm into it if the average resistance offered by the target is 100 newton then the veloctiy with which ot hit the target is?
habib003:
use work and energy relationship formula
f.d=k.e
answer should be 20m/s
don't use. newton's second law of motion bcz here force given is friction
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m=10g=0.01kg
s=2cm=0.02m
F=100N
using work-energy relationship
F.s=1/2 mv^2
100×0.02=1/2 (0.01)×v^2
2=1/2 (0.01)×v^2
4=(0.01)×v^2
v^2=4/0.01
v^2=400
v=20m/s
hope it helps u....
s=2cm=0.02m
F=100N
using work-energy relationship
F.s=1/2 mv^2
100×0.02=1/2 (0.01)×v^2
2=1/2 (0.01)×v^2
4=(0.01)×v^2
v^2=4/0.01
v^2=400
v=20m/s
hope it helps u....
we will never use newtons second law here to get the acceleration
Pr is ka ans10 √2
Mean waha mistake hogii. .. 20 anS to mera bhi agya tha...
yep tumhare pas key galat hogi
Hm
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