Question

Body of mass 25 kg starts from rest. after 5 second it attains a velocity of 25 m/s .find the force acting on it.

Answer 1

Answer:

$\bigstar{\bold{Force\:=\:125\:N}}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Mass of body(m) = 25 kg
• Initial velocity (u) = 0 m/s
• Final velocity (v) = 25 m/s
• Time taken (t) = 5 s

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Force (F) acting on the body

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ By Newton's second law of motion,

  F = m (v - u)/t

→ Substituting the given datas we get,

  F = 25 (25 -0)/5

  F = 125 N

$\boxed{\bold{Force\:=\:125\:N}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ Newton's second law state that the rate of change of momentum is directly proportional to force applied and the change takes place in the direction of the force.

F = ma

→ The unit of force is Newton in SI system and dyne in CGS system.

Answer 2

Given ,

• Mass (m) = 25 kg
• Initial velocity (u) = 0 m/s
• Time (t) = 5 sec
• Final velocity (v) = 25 m/s

We know that ,

Acceleration (a) = (v - u)/t

Thus ,

a = (25 - 0)/5

a = 25/5

a = 5 m/s²

Now , Force = ma

Thus ,

Force = 25 × 5

Force = 125 Newton

$\sf \therefore \underline{The \: force \: acting \: on \: a \: body \: is \: 125 \: newton }$