Question

Body of mass 2kg is dropped from height of 1m. It's kinetic energy as it touches the ground

Answer 1

Answer:

Hey mate,

Body of mass = 2Kg

KE of a body at the ground =

PE of a body at uppermost point

KE = PE

KE = mgh

KE = 2 × 9.8 × 1

KE = 19.6 J

Hope it helps you

Please mark it as branliest

Answer 2

Answer:

Explanation:

The body being dropped from a height acquires kinetic energy during the motion which  is calculated using equation of motion and formula of kinetic energy as follows -

Given: Initial velocity = u = 0

Acceleration a = g

Height h = 1 m

Final velocity v = ?

From equation of motion, we have –

from the kinetic energy formula we have –

K.E. = 20 J