Physics, asked by boss07, 1 year ago

body of mass 5 kg Falls freely from a height hundred metre find initial potential energy second Kinetic and potential energy after 3 seconds

Answers

Answered by Anonymous
31
Hey mate,

Mass of the body m = 5 kg I
initial speed u = 0 
g = 10 m/s2. 

For a freely falling body the final velocity at the end of t s is given by v = u + gt

= 0 + 10 x 3 m/s   

= 30 m/s

 Kinetic energy at the end of 3 s = ½ mv2                                                       

= ½ x 5 kg x (30 m/s)2                                                       = 75 J   

hope this helps you out!
Answered by tanishka164
3

He'll

Here is your answer

mass of body m = 5kg

initial speed = 0

now,g is 100 m/ s2

for freely falling body at the end of its give by v = u+ gt

= 0+10×3

=30m/s2

kinetic energy at the end of 3s= 1/2 mv2

1/2× 25kg × (30 m/s2)2

75 is your answer

I hope it help you

Similar questions