body of mass 5 kg Falls freely from a height hundred metre find initial potential energy second Kinetic and potential energy after 3 seconds
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Answered by
31
Hey mate,
Mass of the body m = 5 kg I
initial speed u = 0
g = 10 m/s2.
For a freely falling body the final velocity at the end of t s is given by v = u + gt
= 0 + 10 x 3 m/s
= 30 m/s
Kinetic energy at the end of 3 s = ½ mv2
= ½ x 5 kg x (30 m/s)2 = 75 J
hope this helps you out!
Mass of the body m = 5 kg I
initial speed u = 0
g = 10 m/s2.
For a freely falling body the final velocity at the end of t s is given by v = u + gt
= 0 + 10 x 3 m/s
= 30 m/s
Kinetic energy at the end of 3 s = ½ mv2
= ½ x 5 kg x (30 m/s)2 = 75 J
hope this helps you out!
Answered by
3
He'll
Here is your answer
mass of body m = 5kg
initial speed = 0
now,g is 100 m/ s2
for freely falling body at the end of its give by v = u+ gt
= 0+10×3
=30m/s2
kinetic energy at the end of 3s= 1/2 mv2
1/2× 25kg × (30 m/s2)2
75 is your answer
I hope it help you
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