Question

body of mass ‘m’ is projected with velocity ‘u’ at an angle ‘theta‘with the horizontal. What is its velocity
at the top most point​

Answer 1

Answer:

x-axis --> ucos(theta) m s^-1

y-axis --> 0

Explanation:

mass = m

velocity = u

angle of projection = theta

Along the horizontal axis, the velocity of the body is always ucos(theta) m s^-1, because there is no acceleration along x-axis. If we resolve a vector u into it's component along theta, it will be ucos(theta).

Along the vertical axis, at the topmost point of the journey, velocity will be zero, because after that point in the journey, it starts coming down due to the acceleration due to gravity.

Answer 2

Given:

A body of mass = m

initial velocity = u

Angle with the horizontal = $\theta$

To Find:

Velocity at the highest point

Solution:

(The law of conservation of momentum states that, when no external forces are acting on a system, then the momentum is conserved. )

Applying the law of conservation of momentum,

mu Cos$\theta$ = mv

v = u Cos$\theta$

Hence the velocity at the highest point would be u Cos$\theta$

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