Question

body of mass m is released from a height h. What potential energy will body possess

when (I) it has fallen by a distance x ( x < h ) (ii) it reaches ground​

Answer 1

Answer:

When the body falls from a height h to h/2, the potential energy is given as 2mgh. The body covers the distance h/2 with a velocity v. We make use of the third equation of motion

to obtain velocity of the body. Hence, at height h/2 the energy possessed is half potential energy and half the kinetic energy.

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Answer 2

Answer:

HEY THERE!!

1) Potential energy U = mg (h-x) and kinetic energy K = mgx

2) Only the kinetic energy K = mgh