Question

body of mass m is thrown horixontally witj velocity v from top of a tower height h toches tje ground at a distance250 m grom foot of yhe tower snother body of mads3 m id thrown with half velocity from tower 4 h height then it eill touch the ground at a distace

Answer 1

Thanks for your question !

Wkt, distance = speed × time we can suppose now, R = v.t.

Now, from above we can say,
h = - 0 + gt 2/2

→ t=√(2h/g) and now ,
→hence R for the second ball = v/2.t = R/2 = 125m.